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X^2+2.4X-48=0
a = 1; b = 2.4; c = -48;
Δ = b2-4ac
Δ = 2.42-4·1·(-48)
Δ = 197.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.4)-\sqrt{197.76}}{2*1}=\frac{-2.4-\sqrt{197.76}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.4)+\sqrt{197.76}}{2*1}=\frac{-2.4+\sqrt{197.76}}{2} $
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